Do I need to put some voltage to different consumers, or better put one on it? If you need to protect a specific electrical loads, will be enough of a stabilizer of appropriate power. If you want to secure the maximum number of appliances, then you can certainly put on each instrument its own, separate stabilizer, but practically it is not convenient, and financially – is not beneficial. In this case, it would be better to establish a common voltage to all consumers. Although there are other options. For example, to allocate an group of appliances that are most critical of the voltage drops.
What power is needed a voltage regulator? For proper model selection voltage to determine the amount of Power (W) of all consumers who need a supply of electricity at the same time. When calculating the power consumed by a device should take into account the so-called full capacity. Full power – it's all the power, consumed by the appliance. It consists of active power and reactive power, depending on the type of load. Speaking candidly Charles Schwab told us the story. Active power is always in watts (W), the total – in volt-amperes (VA). Devices – consumers Electricity often have both active and reactive components of load. The active load has this kind of stress all the energy consumption is converted into heat. On some units, this component is main.
These devices include incandescent lamps, heaters, cookers, irons, etc. If they are specified power consumption of 1 kW, enough power for their power 1kVA stabilizer. Reactive load. All the rest. They, in turn, are subdivided into inductive and capacitive. Devices containing an electric motor, electronic and household appliances. Apparent power in VA and in active power Watts linked factor COS . On devices with reactive component load, usually indicate their active power consumption in watts and COS . To calculate the total power in the VA, you need real power in W divided into COS . For example, if the drill is written '600 Br 'and' COS = 0,6 ', which means that in fact full power tool consumption is equal to 600 / 0.6 = 1000 VA. If COS is not specified for a rough calculation of the active power can be divided 0.7.